char *string1[20] declares an array, named string1, of 20 pointers to char. Thus string1[3] is a pointer to char, and not a char, as would be required for the %c format. Since string1[3] was - if at all - filled via fgets, it contains a 0-terminated string, so you can print it out using. printf("%s\n", string1[3]); WebAug 3, 2024 · (C) char* r = “string1”; printf (“%c”, r [1]); (D) None of the above Solution: Option (A) is valid as p is a pointer pointing to character ‘s’ of “string1”. Using ++p, p will point to character ‘t’ in “string1”. Therefore, *++p will print ‘t’.
Find char in a string C# - CodeProject
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_stricmp, _wcsicmp, _mbsicmp, _stricmp_l, _wcsicmp_l, _mbsicmp_l
WebMar 18, 2024 · The parameter string1 is the name of the string whose length is to be determined. The above function will return the length of the string string1. strcmp () This is the string compare function. It is used for … WebApr 7, 2024 · 注意,与char*不同的是,string不一定以NULL(‘\0’)结束。string长度可以根据length()得到,string可以根据下标访问。所以,不能将string直接赋值给char*。 2、string 转换成 char * 如果要将string直接转换成const char *类型。string有2个函数可以运用。 一个是.c_str(),一个是 WebJul 15, 2024 · In this article, we are going to inspect three different ways of initializing strings in C++ and discuss differences between them. 1. Using char*. Here, str is basically a … longway\\u0027s diner watertown