In an ap sum of first n terms is 3n 2/2
WebMar 29, 2024 · Misc 3 Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3, respectively . Show that S3 = 3 (S2– S1) We know that Sum of n terms = n/2 [2a + (n – 1)d] i.e. Sn = n/2 [2a + (n – 1)d] where a is the first term & d is the common difference of the A.P. It is given that Sum of n terms = S1 i.e. n/2 [2a+ (n – 1)d] = S1 Also, Sum of 2n ... WebIn an AP the sum of first n terms is n/2(3n+5) find the 25th term of the AP CBSE Class 10 Maths#Kcpsir#Class10Mathsclass 10 maths 2024 paper solutionCBSE ...
In an ap sum of first n terms is 3n 2/2
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WebTo find the sum of the first n terms of an arithmetic sequence use the formula, S n = n ( a 1 + a 2) 2 , where n is the number of terms, a 1 is the first term and a n is the last term. Example 1: Find the sum of the first 20 terms of the arithmetic series if a 1 = 5 and a 20 = 62 . S 20 = 20 ( 5 + 62) 2 S 20 = 670 Example 2: WebSep 15, 2024 · Solution: We can use our concept of AP here to solve the problem as follows: Step 1: Calculate the first number divisible by 3 in the given range: 20 = 3 × 6 + 2 a = 20 + (3 - remainder) a = 20 + (3 - 2) a = 21 Step 2: Calculate the Last number (nth) in the given range:- 100 = 3 × 33 + 1 T n = 100 - remainder T n = 100 - 1 Tn = 99
WebWhat is the value of x in the equation 2^(x+1) - 3(2^x) + 2 = 0? If the sum of the first n terms of an arithmetic sequence is given by S = 3n^2 - 2n, what is the common difference of the sequence? what is the degree of a polynomial 5x⁴+6x²-8x-9 WebMar 30, 2024 · Transcript. Question 8 The sum of first n terms of an AP is given by Sn = 2n2 + 3n . Find the sixteenth term of the AP. Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = …
WebThe sum of n terms of an AP can be found using one of the following formulas: S n = n/2 (2a+ (n−1)d) S n = n/2 (a 1 +a n) Here, a = a 1 = the first term, d = the common difference, n = number of terms, a n = n th term, S n … WebAug 9, 2024 · It is an arithmetic progression with first term as 5 and common difference as 6 and 20^(th) term is 119 As sum of n terms of a certain series is given by S_n=2n+3n^2, Sum of 20 terms is 2×20+3×20^2=40+1200=1240. Further, sum of 19 terms is 2×19+3×19^2=38+1083=1121,. Hence 20^(th) term is 1240-1121=119. As sum of 1 term …
WebAug 28, 2024 · Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 …
WebApr 6, 2024 · We are given that, sum of the first 3n terms is equal to the sum of the next n terms. Sum of 3n terms of AP = S 3 n = using above formula, we get: S 3 n = 3 n 2 [ 2 a + ( 3 n − 1) d] Next n term is given by 3n + n = 4n Then, according to condition of question, we have: S 3 n = S 4 n − S 3 n ⇒ 2 S 3 n = S 4 n sighup received fivemWebin an AP the sum of first n terms is 3n2/2 + 13n/2 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first term of two APs are equal and the ratios of … the prince foxWebLet the sum of n terms be given by SnsoSn = 3n²/2+5n/2S1 = 3(1)²/2+5(1)/2= 3/2+5/2= 4So 1st term is 4 say aNowS2 = 3(2)²/2+5(2)/2= 6+5= 11Now a2 =S2−a1=> a2 =11−4= 7Now … the prince family videos youtubethe prince family of d. j. and kyrieWebThe sum of the first term alone is 3 ⋅ 1 + 2 ⋅ 1 2 = 5. So the first term is 5. The sum of the first two terms is 3 ⋅ 2 + 2 ⋅ 2 2 = 14, so the second term is 14 − 5 = 9. The sum of the first … the prince family wallpaperWebJul 21, 2024 · Sn = n 2 (n + 1)(2n + 3) Explanation: Given that n th term of a series is T n = 3n2 + 2n hence, the sum Sn of given series up to first n terms Sn = n ∑ n=1T n = n ∑ n=1(3n2 +2n) = 3 n ∑ n=1n2 + 2 n ∑ n=1n = 3 n 6 (n + 1)(2n + 1) +2 n 2 (n +1) = n 2 (n + 1)(2n + 1 + 2) = n 2 (n + 1)(2n + 3) Answer link the prince feared vs lovedWebJan 8, 2024 · In an AP the sum of first n terms is 3n2/2 + 5n/2 find the 25th term. 9,479 views Jan 7, 2024 253 Dislike Share Save Math Army 81.9K subscribers In an AP the sum of first n... sigh up for affirm with no credit